- ✓$5.8 \mathrm{I}_{0}$
- B$0.2 \mathrm{I}_{0}$
- C$\mathrm{I}_{0}$
- D$3 \mathrm{I}_{0}$
Resultant wave equation
$=A \sin \omega t+A \sin \left(\omega t-\frac{\pi}{4}\right)+A \sin \left(\omega t+\frac{\pi}{4}\right)$
$=\mathrm{A} \sin \omega \mathrm{t}+\sqrt{2} \mathrm{A} \sin \omega \mathrm{t}$
$=(\sqrt{2}+1) \mathrm{A} \sin \omega \mathrm{t}$
Resultant wave amplitude $=(\sqrt{2}+1) \mathrm{A}$
as $I \propto A ^{2}$
so $\frac{\mathrm{I}}{\mathrm{I}_{0}}=(\sqrt{2}+1)^{2}$
$I=5.8 \mathrm{I}_{0}$
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Assertion (A) : The moment of inertia of a rigid body reduces to its minimum value as compared to any other parallel axis when the axis of rotation passes through its centre of mass.
Reason (R): The weight of a rigid body always acts through its centre of mass in uniform gravitational field. Of these statements: