MCQ
Three identical balls are projected with the same speed at angle $30^o, 45^o$ and $60^o$. Their ranges are $R_1 R_2$ and $R_3$ respectively. Then
  • A
    $R_1 = R_2 = R_3$
  • $R_1 = R_3 < R_2$
  • C
    $R_1 < R_2 < R_3$
  • D
    $R_1 > R_2 > R_3$

Answer

Correct option: B.
$R_1 = R_3 < R_2$
b
$30^{\circ}+60^{\circ}=90^{\circ}$

$\therefore \mathrm{R}_{1}=\mathrm{R}_{3}$

and we get maximum range

for $\theta=45^{\circ}$

so $\mathrm{R}_{2}$ will be maximum hence $\mathrm{R}_{1}=\mathrm{R}_{3}<\mathrm{R}_{2}$

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