Three identical resistances $A$, $B$ and $C$ are connected as shown in the given figure. The heat produced will be maximum
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Resistance of $A$ is greater than the resistance of combination of $B$ and $C$, hence voltage drop across $A$ will be greater than that across $B$ or $C$. Also $H = \frac{{{V^2}t}}{R}$
$ \Rightarrow $ $H \propto {V^2}$ so ${H_A} > ({H_B} = {H_C})$ ($R$ = constant)
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