Question
Three light sources A, B and C emit equal amount of radiant energy per unit time. The wavelengths emitted by the three sources are 450nm, 555nm and 700nm respectively. The brightness sensed by an eye for thesources are XA, XB and XC respectively. Then, 
  1. XA > XB, XC > XB
  2. XA > XB, XB > XC
  3. XB > XA, XB > XC
  4. XB > XA, XC > XB

Answer

  1. XB > XA, XB > XC

Explanation:

Wavelength of light B is 555nm. It has the highest luminosity; hence, XB will be highest.

Again, 450nm is nearer to 555nm than 700nm.

$\therefore$ 555 - 450 = 105

But 700 - 555 = 145

So, XA's brightness will be greater than that of XC.

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