Question
Three metallic solid cubes whose edges are $3cm, 4cm$ and 5cm are melted and formed into a single cube. Find the edge of the cube so formed.

Answer

Given, edges of three solid cubes are $3 cm, 4 cm$ and 5 cm , respectively.
$\therefore$ Volume of first cude $=(3)^3=27 cm^3$
Volume of second cube $=(4)^3 64 cm^3$
and volume of third cude $=(5)^3=125 cm^3$
$\therefore$ Sum of volume of three cubes $=(27+64+125)=216 cm^3$
Let the edge of the resulting cude $= Rcm$
Then, volume of the resulting cube, $R ^3=216$
$\Rightarrow R=6 cm$

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