Three plates of common surface area $A$ are connected as shown. The effective capacitance will be
  • A$\frac{{{\varepsilon _0}A}}{d}$
  • B$\frac{{3{\varepsilon _0}A}}{d}$
  • C$\frac{3}{2}\frac{{{\varepsilon _0}A}}{d}$
  • D$\frac{{2{\varepsilon _0}A}}{d}$
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