MCQ
Three plates of common surface area A are connected as shown. The effective capacitance will be


- A$\frac{\varepsilon_0 \mathrm{~A}}{\mathrm{~d}}$
- B$\frac{3\varepsilon_0 A}{d}$
- C$\frac{3}{2} \cdot \frac{\varepsilon_0\mathrm{~A}}{\mathrm{~d}}$
- ✓$\frac{2 \varepsilon_0 A}{d}$