Download App

Mensuration - I (Perimeter and Area of Rectilinear Figures) — Maths STD 7 — Question

Maharashtra BoardEnglish MediumSTD 7MathsMensuration - I (Perimeter and Area of Rectilinear Figures)4 Marks
Question
Through a rectangular field of sides 90m × 60m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the field. if the width of the roads is 3m, find the total area covered by the two roads.
✓

Answer



Length of the rectangular sheet $=90 m$
Breadth of the rectangular sheet $=60 cm$
Area of the rectangular field $=90 m \times 60 m=5400 m^2$
Area of the road $PQRS =90 m \times 3 m=270 m^2$
Area of the road $A B C D=60 m \times 3 m=180 m^2$
Clearly, area of KLMN is common to the two roads.
Thus, area of $KLMN =3 m \times 3 m=9 m^2$
Hence, Area of the roads $=$ Area $(P Q R S)+$ Area $(A B C D)-\operatorname{Area}(K L M N)$
$=(270+180) m^2-9 m^2=441 m^2$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "4 Mark Question" from Mensuration - I (Perimeter and Area of Rectilinear Figures)→Mensuration - I (Perimeter and Area of Rectilinear Figures) — all question types→Maths STD 7 question papers→Maharashtra Board STD 7 question papers→Maharashtra Board question paper generator→

Similar questions

Find x, y, z (whichever is required) from the figure given below:
→
On selling a computer for Rs. 24480, a dealer loses 4%. For how much should he sell it to gain 4%?
→
In Fig. below, ABCD is a rectangle of length AB = 40cm and breadth BC = 25cm. If P, Q, R, S be the mid-points of the sides AB, BC, CD and DA respectively, find the area of the shaded region.
→
Simplify:
$\frac{-11}{39}+\frac{5}{26}+\frac{2}{1}$
→
How much does $a^2-3 a b+2 b^2$ exceed $2 a^2-7 a b+9 b^2$ ?
→
Draw $\triangle\text{ABC}$ in which AC = 6cm, $\angle\text{A}=90^\circ$ and $\angle\text{B}=60^\circ.$
→
(y – 20)° and (y + 30)° are the measures of complementary angles. Find the measure of each angle.
→
What should be added to $\Big(\frac{2}{3}+\frac{3}{5}\Big)$ to get $\frac{-2}{15}?$
→
Sandeep sold a television at a loss of 8%. If he had sold it forRs. 3360 more, he would have gained 6%. For how much did Sandeep buy it?
→
Solve the following equations. Check your result in case.
0.18(5x - 4) = 0.5x + 0.8
→