MCQ
Tick $(\checkmark)$ the correct answer:
$1 - 2ab - (a^2 + b^2) = ?$
$1 - 2ab - (a^2 + b^2) = ?$
- A$(1 + a - b)(1 + a + b)$
- B$(1 + a + b)(1 - a + b)$
- ✓$(1 + a + b)(1 - a - b)$
- D$(1 + a - b)(1 - a + b)$
✓
Answer
Correct option: C.
$(1 + a + b)(1 - a - b)$
C. $(1 + a + b)(1 - a - b)$
Solution:
$1 - 2ab - (a^2 + b^2)$
$= 1 - 2ab - a^2- b^2$
$= 1 - (a^2+ b^2 + 2ab)$
$= 1 - (a + b)^2$
$= (1 + a + b)(1 - a - b)$
Solution:
$1 - 2ab - (a^2 + b^2)$
$= 1 - 2ab - a^2- b^2$
$= 1 - (a^2+ b^2 + 2ab)$
$= 1 - (a + b)^2$
$= (1 + a + b)(1 - a - b)$
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