MCQ
Time taken by the sunlight to pass through a window of thickness 4 mm whose refractive index is 1.5 is
  • A
     $2 \times 10^{-8} sec$
  • B
     $2 \times 10^8 sec$
  •  $2 \times 10^{-11} sec$
  • D
     $2 \times 10^{11} sec$

Answer

Correct option: C.
 $2 \times 10^{-11} sec$
 $2 \times 10^{-11} sec$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A potential difference of $2\,V$ is applied between the opposite faces of a Ge crystal plate of area $1\, cm^{2}$ and thickness $0.5\, mm$. If the concentration of electrons in Ge is $2 × 10^{19}/m^{3}$ and mobilities of electrons and holes are $0.36\frac{{{m^2}}}{{volt - \sec }}$ and $0.14\frac{{{m^2}}}{{volt - \sec }}$ respectively, then the current flowing through the plate will be.....$A$
The wavelength of de$-$Broglie wave is $ 2 \mathrm{~mm} $  then its momentum is  $\left(\mathrm{h}=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}\right)$
Assume a bulb of efficiency $2.5\%$ as a point source. The peak values of electric field produced by the radiation coming from a $100\, W$ bulb at a distance of $3\, m$ is respectively.....$V\,{m^{ - 1}}$
To which region of electromagnetic spectrum the frequency $1\, GHz$ corresponding?
On increasing the temperature of a conductor, its resistance increases because
Three capacitors each of capacity $4\,\mu \,F$ are to be connected in such a way that the effective capacitance is $6\,\mu \,F$. This can be done by
A galvanometer of resistance $100\,\Omega $ has $50\, divisions$ on its scale and has sensitivity of $20\,\mu A / division$. It is to be converted to a voltmeter with three ranges, of $0-2\, V$, $0-10\, V$ and $0-20\, V$. The appropriate circuit to do so is
Two point charges $10C$ and $-10C$ are placed at a certain distance. What is the electric potential of their midpoint?
In an $n-p-n$ transistor $10^{10}$ electron enter the emitter in $10^{-6}\, s$. If $2\%$ of the electrons are lost in the base, the current amplification factor is
A magnetic field can be produced by