MCQ
To solve x + y = 3; 3x–2y – 4 = 0 by determinant method find D.
- A5
- B1
- ✓-5
- D-1
✓
Answer
Correct option: C.
-5
$x+y=3 $
$3 x-2 y=4 $
$D=\left[\begin{array}{cc}
1 & 1 \\
3 & -2
\end{array}\right]=(1 \times-2)-(1 \times 3)=-2-3=-5$
Hence, Option C is correct.
$3 x-2 y=4 $
$D=\left[\begin{array}{cc}
1 & 1 \\
3 & -2
\end{array}\right]=(1 \times-2)-(1 \times 3)=-2-3=-5$
Hence, Option C is correct.
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