- A$9$
- ✓$13$
- C$10$
- D$6$
$\therefore m_l = 0$ will be $= 2 + 2 + 2 + 2 + 2 + 1 + 2 = 13$
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(Given : Atomic masses: $C$ : $12.0\, u$, $H : 1.0\, u , N : 14.0\, u , Br : 80.0\, u ]$
(Image)
Pre-exponential factors for the forward and backward reactions are $10^{15} \mathrm{~s}^{-1}$ and $10^{11} \mathrm{~s}^{-1}$, respectively. If the value of $\log \mathrm{K}$ for the reaction at $500 \mathrm{~K}$ is $6$ , the value of $\left|\log \mathrm{k}_{\mathrm{b}}\right|$ at $250 \mathrm{~K}$ is $\qquad$
$[\mathrm{K}=$ equilibrium constant of the reaction
$\mathrm{k}_{\mathrm{f}}=$ rate constant of forward reaction
$\mathrm{k}_{\mathrm{b}}=$ rate constant of backward reaction]
(Rounded off to the nearest integer)
(Mass of $Li ^{3+}=8.3$ mass of proton)