MCQ
Total number of electrons in $“Cu”$ atom having $m_l = 0$
- A$9$
- ✓$13$
- C$10$
- D$6$
$\therefore m_l = 0$ will be $= 2 + 2 + 2 + 2 + 2 + 1 + 2 = 13$
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Compound $\rightarrow$ O.State of $C.M.I.$
$(i)$ $4.5\, mL$ $\quad (ii)$ $4.5\, mL$ $\quad (iii)$ $4.4\, mL$
$(iv)$ $4.4\, mL$ $\quad (v)$ $4.4\, mL$
If the volume of oxalic acid taken was $10.0 \,mL$ then the molarity of the $NaOH$ solution is .... $M.$ (Rounded-off to the nearest integer)