MCQ
Transition element makes complex compound due to
- ✓Presence of empty $d-$ orbital
- Blarge size
- CVariable valency
- Dpresence of $2e^-$
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$\left(R=0.083\, L\, \operatorname{bar} \,\mathrm{K}^{-1} \,\mathrm{~mol}^{-1}\right)$
$'A'$ on reaction with sodium hypoiodite gives $'B',$ which on further heating with soda lime gives ' $C$ '. The compound ' $C$ ' is $....... .$