MCQ
Transition elements are coloured
- ADue to small size
- BDue to metallic nature
- ✓Due to unpaired $d -$ electrons
- DAll of these
✓
Answer
Correct option: C.
Due to unpaired $d -$ electrons
c
(c)Due to unpaired $d-$ electrons.
(c)Due to unpaired $d-$ electrons.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following is paramagnetic
$C + {O_2} \to C{O_2};\,\Delta H = X$
→$CO + \frac{1}{2}{O_2} \to C{O_2};\,\Delta H = Y$
Then the heat of formation of $CO$ is
Product $(A)$ in this reaction is
→Match list $- I$ and List $- II.$
→| List $-I$ | List $-II$ | ||
|
$(a)$ |
$\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - Cl \to R - CHO} \end{array}$ |
$(i)$ |
$Br _{2} / NaOH$ |
| $(b)$ | $\begin{array}{*{20}{c}} {R - C{H_2} - COOH \to R - CH - COOH} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl} \end{array}$ |
$(ii)$ | $H _{2} / Pd - BaSO _{4}$ |
| $(c)$ | $\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - N{H_2} \to R - N{H_2}} \end{array}$ |
$(iii)$ | $Zn ( Hg ) /$ Conc. $HCl$ |
| $(d)$ | $\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - C{H_3} \to R - C{H_2} - C{H_3}} \end{array}$ |
$(iv)$ | $Cl _{2}$ / Red $P , H _{2} O$ |
Choose the correct answer from the options given below:
Which one of the following has the regular tetrahedral structure
→(Atomic no. : $B = 5,S = 16,Ni = 28,Xe = 54$)
Which of the following is in the increasing order of the ionic character
$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - C \equiv CH}
\end{array}\xrightarrow{{excess\,HBr}}$
→{C{H_3}\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - C \equiv CH}
\end{array}\xrightarrow{{excess\,HBr}}$
The product of the above reaction is
According to Heisenberg’s uncertainty principle, the product of uncertainties in position and velocities for an electron of mass $9.1 \times {10^{ - 31}}\,kg$ is
→$ \, $
→The $ IUPAC$ name of the complex $\left[ {Pt{{\left( {N{H_3}} \right)}_2}C{l_2}} \right]$ is
→