MCQ
Transition elements form complexes readily because:
- ASmall size of cation
- BLarge ionic Charge
- CVacant d orbitals
- DAll the above
Explanation:
Transition elements form complexes readily because
Due to lower size and higher charge, they have high charge density.
They have vacant d orbital in which a ligand can donate its electron and form complex.
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$B.$ $N , N$ -Dimethylaniline
$C.$ N-Methyl aniline
$D.$ Benzenamine
Choose the correct order of basic nature of the above amines.
| List$-I$ | List$-II$ |
| $(a)$ $\left[ Co \left( NH _{3}\right)_{6}\right]\left[ Cr ( CN )_{6}\right]$ |
$(i)$ Linkage isomerism |
| $(b)$ $\left[ Co \left( NH _{3}\right)_{3}\left( NO _{2}\right)_{3}\right]$ |
$(ii)$Solvate isomerism |
| $(c)$ $\left[ Cr \left( H _{2} O \right)_{6}\right] Cl _{3}$ |
$(iii)$ Co-ordination isomerism |
| $(c)$ $cis-[CrCl$ $\left._{2}(\text { ox })_{2}\right]^{3-}$ | $(iv)$ Optical isomerism |
Choose the correct answer from the options given below:
