- AHigh m.p. and b.p. of transition metals.
- BPresence of vacant d-orbitals.
- CPresence of one or more unpaired d-electrons.
- DTheir less electropositive nature as compared to the elements of groups IA and IIA.
Explanation:
The general outer electronic configuration of d-block elements is (n - 1)d1−10 ns1−2. Hence, d - block elements often have one or more unpaired d - electrons.
Due to presence of these unpaired electrons, transition elements show paramagnetism.
Therefore transition elements are often paramagnetic due to presence of one or more unpaired d electrons.
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$6 OH ^{-}+ Cl ^{-} \rightarrow ClO _{3}^{-}+3 H _{2} O +6 e ^{-}$
If only $60 \%$ of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce $10\, g$ of $KCIO _{3}$ using a current of $2\, A$ is..........
(Given : $F =96,500\, C\, mol ^{-1}$ molar mass of $\left. KClO _{3}=122\,gmol ^{-1}\right)$

