MCQ
Transition state structure of the substrate formed during an enzymatic reation is:
- ATemporary but stable.
- BPermanent but unstable.
- ✓Temporary and unstable.
- DPermanent and stable.
✓
Answer
Correct option: C.
Temporary and unstable.
During an enzymatic reaction, a substrate goes through a transition state before it becomes a product.
It is proposed that the transition state is bound more strongly than either the substrate or the product, however, the transition state is inherently unstable and are transient.
It is proposed that the transition state is bound more strongly than either the substrate or the product, however, the transition state is inherently unstable and are transient.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The correct statement about the synthesis of erythritol $(C(CH_2OH)_4)$ used in the preparation of $PETN$ is
→The acidity of alpha hydrogen of the carbonyl group is due to:
What is the standard reduction potential $(E^o)$ for $Fe^{3+} \to Fe$ ? ............... $\mathrm{V}$
→Given that :
$F{e^{2 + }} + 2{e^ - } \to Fe;$ ${E^o}_{F{e^{2 + }}/Fe} = - 0.47\,V$
$F{e^{3 + }} + {e^ - } \to F{e^{2 + }};$ ${E^o}_{F{e^{3 + }}/F{e^{2 + }}} = + 0.77\,V$
The interstital hole is called tetrahedral because ?
Which of the following does not produces $NO_2$ gas with conc. $HNO_3$ ?
→The decomposition of phosphine $(PH_3)$ on tungsten at low pressure is a first-order reaction. It is because the
→$Cu^+ + e^-\to Cu$ ; $E^o = X_1V$
→$Cu^{2+} + 2e^-\to Cu$ ; $E^o = X_2V$
Then For $Cu^{2+} + e^- \to Cu^+$ $;E^o$ will be ?
$C$ is
→Correct sequence of $CO$ bond order in given compounds is :
→$(P)\, Fe(CO)_5\,\,\, (Q)\,CO\,\,\, (R)\, H_3B \leftarrow CO\,\,\,(S)\, [Mn(CO)_5]^-$
Match List-$I$ with List-$II.$
→Choose the correct answer from the options given below: