MCQ
$\triangle\text{ABC}$ is an isosceles triangle in which $\angle\text{C}=90^\circ$ If $AC = 6\ cm,$ then $AB =$
- ✓$6\sqrt{2}\text{ cm}.$
- B$6\text{ cm}.$
- C$2\sqrt{6}\text{ cm}.$
- D$4\sqrt{2}\text{ cm}.$
✓
Answer
Correct option: A.
$6\sqrt{2}\text{ cm}.$
$\triangle\text{ABC}$ is an isosceles with $\angle\text{C}=90^\circ$
$AC=BC$
$AC=6 \ cm$
$AB^2=AC^2+BC^2 \ ($Pythagoras Theorem$)$
$(6)^2+(6)^2=36+36=72(AC=BC)$
$\text{AB}=\sqrt{72}=\sqrt{(36\times2}=6\sqrt{2}\text{ cm}.$
$AC=BC$
$AC=6 \ cm$
$AB^2=AC^2+BC^2 \ ($Pythagoras Theorem$)$
$(6)^2+(6)^2=36+36=72(AC=BC)$
$\text{AB}=\sqrt{72}=\sqrt{(36\times2}=6\sqrt{2}\text{ cm}.$
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