Question
$\triangle\text{ABC}$ is isosceles with AB = AC. Line segment AD bisects $\angle\text{A}$ and meets the base BC in D.
Is $\triangle\text{ADB}\cong\triangle\text{ADC}?$

Answer

We have AB = AC (Given)
$\angle\text{BAD}=\angle\text{CAD}$ (AD bisects $\angle\text{BAC}$ )
Therefore by SAS condition of congruence, $\triangle\text{ABD}\cong\triangle\text{ACD}$

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