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Triangles — Maths STD 10 — Question

Maharashtra BoardEnglish MediumSTD 10MathsTriangles1 Mark
MCQ
$\triangle\text{ABC}\sim\triangle\text{DEF}$ such that $AB = 9.1\ cm$ and $DE = 6.5\ cm.$ If the perimeter of $\triangle\text{DEF}$ is $25\ cm$, what is the perimeter of $\triangle\text{ABC}?$
  • ✓
    $35\ cm$
  • B
    $28\ cm$
  • C
    $42\ cm$
  • D
    $40\ cm$
✓

Answer

Correct option: A.
$35\ cm$
$\triangle\text{ABC}\sim\triangle\text{DEF}$
$\Rightarrow\frac{\text{Perimeters of }\triangle\text{ABC}}{\text{Perimeters of }\triangle\text{DEF}}=\frac{\text{AB}}{\text{DE}}$
$\Rightarrow\frac{\text{Perimeters of }\triangle\text{ABC}}{25}=\frac{9.1}{6.5}$
$\Rightarrow\text{Perimeters of }\triangle\text{ABC}=\frac{9.1\times25}{6.5}$
$\Rightarrow\text{Perimeters of }\triangle\text{ABC}=35\text{cm}$

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