\(\therefore \) \({v_{\max }} = a\omega = \frac{{10}}{\pi } \times 2000\,\pi = 200m/\sec \)
and \(\omega = \frac{{2\pi }}{T} \Rightarrow 2000\,\pi = \frac{{2\pi }}{T}\)==> \(T = {10^{ - 3}}\,sec\)
(વાયુનો અચળાંક $R=8.3 \;JK ^{-1} mol ^{- 1}$ લો)
(હવામાં ધ્વનિની ઝડપ $=330\, ms^{-1}$)