Coordination Compounds — Chemistry STD 12 Science — Question

$\mathrm{M}(\mathrm{s}) \mid \mathrm{M}^{+}$(aq; $0.05$ molar) || $\mathrm{M}^{+}(\mathrm{aq}), 1$ molar) $\mid \mathrm{M}(\mathrm{s})$

For the above electrolytic cell the magnitude of the cell potential $\left|E_{\text {cell }}\right|=70 \mathrm{mV}$.

$1.$ For the above cell

$(A)$ $\mathrm{E}_{\text {cell }}<0 ; \Delta \mathrm{G}>0$ $(B)$ $\mathrm{E}_{\text {cell }}>0 ; \Delta \mathrm{G}<0$

$(C)$ $\mathrm{E}_{\text {cell }}<0 ; \Delta \mathrm{G}^{\circ}>0$ $(D)$ $\mathrm{E}_{\text {cell }}>0 ; \Delta \mathrm{G}^{\circ}>0$

$2.$ If the $0.05$ molar solution of $\mathrm{M}^{+}$is replaced by $0.0025$ molar $\mathrm{M}^{+}$solution, then the magnitude of the cell potential would be

$(A)$ $35 \mathrm{mV}$ $(B)$ $70 \mathrm{mV}$ $(C)$ $140 \mathrm{mV}$ $(D)$ $700 \mathrm{mV}$

Give the answer question $1,2.$ 

$\mathrm{BrO}_{4}^{-} \stackrel{1.82 \mathrm{V}}{\longrightarrow} \mathrm{BrO}_{3}^{-} \stackrel{1.5 \mathrm{V}}{\longrightarrow} \mathrm{HBrO}$$\stackrel{1.0652 \mathrm{V}}{\longrightarrow} \mathrm{Br}_{2} \stackrel{1.595 \mathrm{V}}{\longrightarrow} \mathrm{Br}^{-}$

Then the species undergoing disproportionation is