Question
Tube A has both ends open, while B has on end closed otherwise the two tubes are identical. What Is the ratio of fundamental frequency of the tubes A and B?

Answer

The fundamental frequency for tube A with both ends open is $f _{ A }=\frac{v}{2 L }$
The fundamental frequency for tube $B$ with one end closed is $f _{ B }=\frac{v}{4 L }$ $\frac{f_{ A }}{f_{ B }}=\frac{v / 2 L }{v / 4 L }=2 \Rightarrow f_{ A }: f_{ B }=2: 1$

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