MCQ
Turnbull's blue is:
- AFe3[Fe(CN)6]2
- BK4Fe(CN)6
- CK3Fe(CN)6
- DNa4Fe(CN)6
Explanation:
Turnbull's blue is Fe3[Fe(CN)6]2.
The structure is as follows:

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At $t = 800\,s$, $[N_2O_5] = 1.45\,mol\,L^{-1}$
At $t = 1600\,s$, $[N_2O_5] = 0.88\,mol\,L^{-1}$
Sucrose $\xrightarrow[{Cleavage\,\,(Hydrolysis)}]{{Gly\cos idic\,bond}}A + B\xrightarrow[{{\text{reagent}}}]{{{\text{Seliwanoff 's}}}}?$