MCQ
Turnbull's blue is:
- ✓$\mathrm{Fe}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$
- B$\mathrm{\sim K}_4 \mathrm{Fe}(\mathrm{CN})_6$
- C$\mathrm{\sim K}_3 \mathrm{Fe}(\mathrm{CN})_6$
- D$\mathrm{Na}_4 \mathrm{Fe}(\mathrm{CN})_6$
✓
Answer
Correct option: A.
$\mathrm{Fe}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$
Turnbull's blue is $\mathrm{Fe}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$.
The structure is as follows:
The structure is as follows:
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