Question
Two angles of a triangle are equal and the third angle is greater than each of those angles by 30º. Determine all the angles of the triangle.
✓
Answer
Given that,
Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°.
Let x, x, x + 30° be the angles of a triangle
We know that,
Sum of all angles in a triangle is 180°
x + x + x + 30° = 180°
3x + 30° = 180°
3x = 180° - 30°
3x = 150°
x = 50°
Therefore, the three angles are 50°, 50°, 80°.
Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°.
Let x, x, x + 30° be the angles of a triangle
We know that,
Sum of all angles in a triangle is 180°
x + x + x + 30° = 180°
3x + 30° = 180°
3x = 180° - 30°
3x = 150°
x = 50°
Therefore, the three angles are 50°, 50°, 80°.
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