Question
Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls.
Find the probability that both balls are red.

Answer

Given: A box containing 10 black and 8 red balls.
Total number of balls in box = 18
Probability of getting a red ball in first draw = $\frac{8}{18}=\frac{4}{9}$ 
As the ball is replaced after first throw,
Hence, Probability of getting a red ball in second draw = $\frac{8}{18}=\frac{4}{9}$ 
Now, Probability of getting both balls red = $\frac{4}{9} \times \frac{4}{9}=\frac{16}{81}$

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