Two bulbs of 500, watt and 200, watt are manufactured to operate on 220, volt line. The ratio of heat produced in 500, W and

Q: Two bulbs of $500\, watt$ and $200\, watt$ are manufactured to operate on $220\, volt$ line. The ratio of heat produced in $500\, W$ and $200\, W$, in two cases, when firstly they are joined in parallel and secondly in series, will be

a (a) Resistance ${R_1}$ of $500\, W$ bulb $ = \frac{{{{(220)}^2}}}{{500}}$ Resistance ${R_2}$ of $200\, W$ bulb $ = \frac{{{{(220)}^2}}}{{200}}$ When joined in parallel, the potential difference across both the bulbs will be same. Ratio of heat produced $ = \frac{{{V^2}/{R_1}}}{{{V^2}/{R_2}}} = \frac{{{R_2}}}{{{R_1}}} = \frac{5}{2}$ When joined in series, the same current will flow through both the bulbs. Ratio of heat produced $ = \frac{{{i^2}{R_1}}}{{{i^2}{R_2}}} = \frac{{{R_1}}}{{{R_2}}} = \frac{2}{5}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Two bulbs of $500\, watt$ and $200\, watt$ are manufactured to operate on $220\, volt$ line. The ratio of heat produced in $500\, W$ and $200\, W$, in two cases, when firstly they are joined in parallel and secondly in series, will be

A$\frac{5}{2},\,\frac{2}{5}$
B$\frac{5}{2},\,\frac{5}{2}$
C$\frac{2}{5},\,\frac{5}{2}$
D$\frac{2}{5},\,\frac{2}{5}$

Diffcult

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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