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Electrostatics — Physics STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 SciencePhysicsElectrostatics1 Mark
MCQ
Two capacitances of capacity $C_1$ and $C_2$ are connected in series and potential difference V is applied across it. Then the potential difference across $C_1$ will be
  • A
    ${V} \frac{C_2}{C_1}$
  • B
    $V \frac{C_1+C_2}{C_1}$
  • ✓
    $V \frac{C_2}{C_1+C_2}$
  • D
    $V \frac{C_1}{C_1+C_2}$
✓

Answer

Correct option: C.
$V \frac{C_2}{C_1+C_2}$
(c) $V \frac{C_2}{C_1+C_2}$

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