Two capacitors $C_1$ and $C_2=$ $2 C _1$ are connected in a circuit with a switch between them as shown in the figure.Initially the switch is open and $C _1$ holds charge $Q$. The switch is closed. At steady state, the charge on each capacitor will be
Medium
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(b)
In steady state, both the capacitors are at the same potential, i.e., $\frac{ Q _1}{ C _1}=\frac{ Q _2}{ C _2}$ or $\frac{ Q _1}{ C }=\frac{ Q _2}{2 C }$ or $Q _2=2 Q _1$
Also $Q _1+ Q _2= Q$
$\therefore Q _1=\frac{ Q }{3}, Q _2=\frac{2 Q }{3}$
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