MCQ
Two capacitors each having capacitance $C$ and breakdown voltage $V$ are joined in series. The capacitance and the breakdown voltage of the combination will be:
  • A
    $\text{2C}\ \text{and}\ \text{2V}$
  • B
    $\frac{\text{C}}{2}\ \text{and}\ \frac{\text{V}}{2}$
  • C
    $\text{2C}\ \text{and}\ \frac{\text{V}}{2}$
  • $\frac{\text{C}}{2}\ \text{and}\ \text{2V}$

Answer

Correct option: D.
$\frac{\text{C}}{2}\ \text{and}\ \text{2V}$
Since the voltage gets added up when the capacitors are connected in series, the voltage of the combination is $2V.$
Also, the capacitance of a series combination is given by
$\frac{1}{\text{C}_{\text{net}}}=\frac{1}{\text{C}_1}+\frac{1}{\text{C}_2}$
Here,
$C_{​net}​ =$ Net capacitance of the combination
$\text{C}_1=\text{C}_2=\text{C}$
$\therefore\text{C}_{\text{net}}=\frac{\text{C}}{2}$

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