Question
Two capacitors each of capacity 2 μF are connected in parallel. This system is connected in series with the third capacitor of 12μF capacity. Find the equivalent capacity of the system.
✓
Answer
Here, $C_1$ and $C_2$ are in parallel.
$
\therefore C_{A B}=C_1+C_2=2 \mu F+2 \mu F=4 \mu F
$
Here, $C_{A B}$ and $C_3$ are in series,
$
\therefore \frac{1}{ C _{ AC }}=\frac{1}{4 \mu}+\frac{1}{12 \mu}
$
$
\therefore C_{A C}= 3 \mu F
$
The equivalent capacity of the system is $3 \mu F$.
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