Question
Two charged capacitors have their outer plates fixed and inner plates connected by a spring of force constant ' $k$ '. The charge on each capacitor is q. Find the extension in the spring at equilibrium

Answer

(a)

$F=k x=\frac{q^2}{2 A \varepsilon_0}$

$x=\frac{q^2}{2 A \varepsilon_0 k}$

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