Question
Two charged particles traverse identical helical paths in a completely opposite sense in a uniform magnetic field $B = B_0 \hat k$ .
✓
Answer
For given pitch, $d$ corresponds to charged particle, we have
$\frac{\mathrm{q}}{\mathrm{m}}=\frac{2 \pi \mathrm{v} \cos \theta}{\mathrm{B}}=\mathrm{constant} \Rightarrow\left(\frac{\mathrm{e}}{\mathrm{m}}\right)_{1}+\left(\frac{\mathrm{e}}{\mathrm{m}}\right)_{2}=0$
Note Consider $e$ in place of $\mathrm{q}$ in solution.
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