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Electromagnetic Induction — Physics STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 SciencePhysicsElectromagnetic Induction1 Mark
Question
Two coils are at fixed locations. When coil $1$ has no current and the current in coil $2$ increases at the rate of $15.0As^{-1},$ the emf in coil $1$ is $25\ mV.$ When coil $2$ has no current and coil $1$ has a current of $3.6A,$ the flux linkage in coil $2$ is.
✓

Answer

$\mid\text{M}\mid=\frac{\text{e}_1}{\big(\frac{\text{di}_2}{\text{dt}}\big)}=\frac{\phi_2}{\text{i}_1}$
$\therefore\phi_2=\frac{\text{e}_1\text{i}_1}{(\frac{\text{di}^2}{\text{dt}})}=\frac{(25.0\times10^{-3})(3.6)}{(15)}$
$=6\times10^{-3}=6\text{mWb}$

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