MCQ
Two complementary angles are in the ratio $1 : 9.$ The angles are:
- A$54^\circ , 36^\circ$
- ✓$9^\circ , 81^\circ$
- C$10^\circ , 90^\circ$
- D$11^\circ , 79^\circ$
Let the angles be $x$ and $9x$ Sum of complementary angles is $90^\circ $
$\Rightarrow x + 9x = 90^\circ $
$\Rightarrow 10x = 90^\circ $
$\Rightarrow x = 9^\circ $
So the angles are $1 \times 9^\circ = 9^\circ $
$9 \times 9^\circ = 81^\circ $
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