MCQ
Two complementary angles are such that two times the measure of one is equal to three times the measure of the other. The measure of the larger angle is:
- A$72^\circ$
- B$108^\circ$
- C$36^\circ$
- ✓$54^\circ$
Let the complementary angles be $x$ and $(90^\circ − x).$
Then, $2x = 3(90^\circ − x)$
$\Rightarrow2{\text{x}}=270^\circ-3\text{x}$
$\Rightarrow5\text{x}=270^\circ$
$\Rightarrow\text{x}=\frac{270^\circ}{5}=54^\circ$
$\therefore$ The two angles are $54^\circ , 36^\circ $
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