MCQ
Two complementary angles differ by $20^\circ .$ The smaller angle is:
- A$55^\circ $
- B$25^\circ $
- C$65^\circ $
- ✓$35^\circ $
Let the smaller angle be $x.$
Then,The larger angle $= (x + 20^\circ )$
As, the sum of the two complementary angles is always $90^\circ .$
$\Rightarrow x + (x + 20^\circ ) = 90^\circ $
$\Rightarrow 2x + 20^\circ = 90^\circ $
$\Rightarrow 2x = 90^\circ - 20^\circ $
$\Rightarrow 2x = 70^\circ $
$\Rightarrow\text{x}=\frac{70^\circ}{2} ($By transposing $2$ to $\text{R.H.S.)}$
$\therefore\text{x}=35^\circ$
So, the smaller angle is $35^\circ .$
Hence, the correct alternative is option $(d).$
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