Question
Two complementary angles differ by $8^\circ .$ Find the angles.
✓
Answer
Sum of two complementary angles $= 90^\circ $
Let first angle $= x$
Then second $= 90^\circ - x $
$x - (90^\circ - x) = 8 $
$\Rightarrow x - 90^\circ + x = 8 $
$\Rightarrow 2x = 8 + 90^\circ $
$\Rightarrow 2x = 98^\circ $
$ \Rightarrow x = 49^\circ $
First angle $= 49^\circ $ And second angle $= 90^\circ - 49^\circ = 41^\circ $
Hence angles are $41^\circ , 49^\circ $
Let first angle $= x$
Then second $= 90^\circ - x $
$x - (90^\circ - x) = 8 $
$\Rightarrow x - 90^\circ + x = 8 $
$\Rightarrow 2x = 8 + 90^\circ $
$\Rightarrow 2x = 98^\circ $
$ \Rightarrow x = 49^\circ $
First angle $= 49^\circ $ And second angle $= 90^\circ - 49^\circ = 41^\circ $
Hence angles are $41^\circ , 49^\circ $
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Draw a solid using the top. side and front views as shown below. [Use Isometric dot paper]. 
By what number should we multiply $\frac{-1}{6}$ so that the product may be $\frac{-23}{9}$ ?
→Find: $8.5\%$ of $5\ kg$
→The total cost of $3$ tables and $2$ chairs is $Rs. 1850.$ If a table costs $Rs. 75$ more than a chair, find the price of each.
→Verify the following.
(i) $18 \times[7+(-3)]=[18 \times 7]+[18 \times(-3)]$
(ii) $(-21) \times[(-4)+(-6)] =[(-21) \times(-4)]+[(-21) \times(-6)]$
→(i) $18 \times[7+(-3)]=[18 \times 7]+[18 \times(-3)]$
(ii) $(-21) \times[(-4)+(-6)] =[(-21) \times(-4)]+[(-21) \times(-6)]$
Express the following numbers in standard form.
3908.78
3908.78
$D$ is a point on side $BC$ of a $\triangle \text{CAD}$ is joined. Name all the triangles that you can observe in the figure. How many are they?
→Rohan's mother gave him $Rs. 3 x y^2$ and his father gave him $Rs. 5\left(x y^2+2\right)$. Out of this total money he spent $Rs. (10 3 x y^2 ) $ on his birthday party. How much money is left with him?
→Find:$\frac{2}{3}\text{ of }\frac{9}{16}$
→→