MCQ
Two dice are rolled. If a random variable X is defined as the absolute difference of the two numbers that appear on them, then the mean of X is
- A$0$
- B$\frac{13}{18}$
- C$\frac{19}{9}$
- ✓$\frac{35}{18}$
✓
Answer
Correct option: D.
$\frac{35}{18}$
(D)
Possible values of X are $0,1,2,3,4,5$
$\therefore$ Probability distribution of X is given as
$\begin{aligned} \therefore \text { Mean } & =0+1\left(\frac{10}{36}\right)+2\left(\frac{8}{36}\right)+3\left(\frac{6}{36}\right)+4\left(\frac{4}{36}\right)+5\left(\frac{2}{36}\right) \\ & =\frac{35}{18}\end{aligned}$
Possible values of X are $0,1,2,3,4,5$
$\therefore$ Probability distribution of X is given as
| X = x | 0 | 1 | 2 | 3 | 4 | 5 |
| P(X = x) | $\frac{6}{36}$ | $\frac{10}{36}$ | $\frac{8}{36}$ | $\frac{6}{36}$ | $\frac{4}{36}$ | $\frac{2}{36}$ |
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