Question
Two dice are rolled once. Find the probability that:
  1. the numbers on two dice are different.
  2. the total of numbers on the two dice is at least.

Answer

P(Numbers on two dice are different) $= \frac{30}{36} =\frac {5}{6}$ P (Total of numbers on two dice is atleast 4) $=\frac{33}{36} = \frac{11}{12}$

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