Two dice are thrown simultaneously. The probability of getting a pair of aces is
A$\frac{1}{36}$
B$\frac{1}{3}$
C$\frac{1}{6}$
D
None of these.
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A$\frac{1}{36}$
Required probability = Probability of ace in first throw + Probability of ace in second throw
$=\frac{1}{6}\times\frac{1}{6}=\frac{1}{36}$
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