MCQ
Two dice are thrown simultaneously. The probability of getting a pair of aces is
  • A
    $\frac{1}{36}$
  • B
    $\frac{1}{3}$
  • C
    $\frac{1}{6}$
  • D
    None of these.

Answer

  1. $\frac{1}{36}$

Solution:

Required probability = Probability of ace in first throw + Probability of ace in second throw

$=\frac{1}{6}\times\frac{1}{6}=\frac{1}{36}$

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