Probability — Maths STD 11 Science — Question

Two dice are thrown.

∴ n(S) = 36

Getting two numbers whose product is even, i.e., one of the two numbers must be even.

Let event A: Getting even number on first dice,

event B: Getting even number on second dice.

n(A) = 18, n(B) = 18, n(A ∩ B) = 9

Required probability = P(A ∩ B)

$\begin{aligned} & =\frac{n(A)+n(B)-n(A \cap B)}{n(S)} \\ & =\frac{18+18-9}{36} \\ & =\frac{3}{4}\end{aligned}$