MCQ
Two dice are thrown together. The probability that at least one will show its digit $6$ is
- ✓$\frac{{11}}{{36}}$
- B$\frac{{36}}{{11}}$
- C$\frac{5}{{11}}$
- D$\frac{1}{6}$
Sample space = $\left\{ \begin{array}{l}(6,\,\,1)\,\,(6,\,\,2)\,\,(6,\,\,3)\,\,(6,\,\,4)\$6,\,\,5)\,\,(1,\,\,6)\,\,(2,\,\,6)\,\,(3,\,\,6)\$4,\,\,6)\,\,(5,\,\,6)\,\,(6,\,\,6)\end{array} \right\}$
Probability of at least one $6$
$ = P$(one $6$) $ + P$(both $6$)
$ = \frac{{10}}{{36}} + \frac{1}{{36}} = \frac{{11}}{{36}}.$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.