MCQ
Two dice are thrown together. The probability that at least one will show its digit $6$ is
  • $\frac{{11}}{{36}}$
  • B
    $\frac{{36}}{{11}}$
  • C
    $\frac{5}{{11}}$
  • D
    $\frac{1}{6}$

Answer

Correct option: A.
$\frac{{11}}{{36}}$
a
(a) Number of ways $ = 6 \times 6 = 36$

Sample space = $\left\{ \begin{array}{l}(6,\,\,1)\,\,(6,\,\,2)\,\,(6,\,\,3)\,\,(6,\,\,4)\$6,\,\,5)\,\,(1,\,\,6)\,\,(2,\,\,6)\,\,(3,\,\,6)\$4,\,\,6)\,\,(5,\,\,6)\,\,(6,\,\,6)\end{array} \right\}$

Probability of at least one $6$

$ = P$(one $6$) $ + P$(both $6$)

$ = \frac{{10}}{{36}} + \frac{1}{{36}} = \frac{{11}}{{36}}.$

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