Two different liquids are flowing in two tubes of equal radius. The ratio of coefficients of viscosity of liquids is $52:49$ and the ratio of their densities is $13:1$, then the ratio of their critical velocities will be
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(a) Critical velocity $v = {N_R}\frac{\eta }{{\rho r}}$

==> $\frac{{{v_1}}}{{{v_2}}} = \frac{{{\eta _1}}}{{{\eta _2}}} \times \frac{{{\rho _2}}}{{{\rho _1}}} = \frac{{52}}{{49}} \times \frac{1}{{13}} = \frac{4}{{49}}$.

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