MCQ
Two different liquids of same mass are kept in two identical vessels, which are placed in a freezer that extracts heat from them at the same rate causing each liquid to transform into a solid. The schematic figure below shows that temperature $T$ versus time $t$ plot for the two materials. We denote the specific heat of materials in the liquid (solid) states to be $C_{L 1}$ $\left(C_{S 1}\right)$ and $C_{L 2}\left(C_{S 2}\right)$, respectively. Choose the correct option given below.
  • A
    $C_{L 1} < C_{L 2}$ and $C_{S 1} < C_{S 2}$
  • $C_{L 1} > C_{L 2}$ and $C_{S 1} < C_{S 2}$
  • C
    $C_{L 1} > C_{L 2}$ and $C_{S 1} > C_{S 2}$
  • D
    $C_{L 1} < C_{L 2}$ and $C_{S 1} > C_{S 2}$

Answer

Correct option: B.
$C_{L 1} > C_{L 2}$ and $C_{S 1} < C_{S 2}$
b
(b)

Let $Q=$ rate of heat removal.

Then, $Q \cdot t=m c T$

$\Rightarrow T=\frac{Q}{m c} \cdot t$

Comparing this with $y=m x$,

Slope of $T-t$ line $\propto \frac{1}{\text { Specific heat }}$

From graph,

$\therefore C_{S 1} < C_{S 2}$

$\text { and } C_{L 1} > C_{L 2}$

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