MCQ
Two droplets merge with each other and forms a large droplet. In this process
- ✓Energy is liberated
- BEnergy is absorbed
- CNeither liberated nor absorbed
- DSome mass is converted into energy
$W = T(\Delta A) = ({\rm{negative}})$ i.e. energy is released.
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${y}_{1}={A}_{1} \sin {k}({x}-v {t}), {y}_{2}={A}_{2} \sin {k}\left({x}-{vt}+{x}_{0}\right) .$ Given amplitudes ${A}_{1}=12\, {mm}$ and ${A}_{2}=5\, {mm}$ ${x}_{0}=3.5\, {cm}$ and wave number ${k}=6.28\, {cm}^{-1}$. The amplitude of resulting wave will be $......\,{mm}$
Main scale reading : $0\ mm$
Circular scale reading : $52\ divisions$
Given that $1\ mm$ on main scale corresponds to $100$ divisions of the circular scale. The diameter of wire from the above data is: